Example:
a) What is the period of this waveform?
b) Find equations representing the waveform over the first period
(ie 0 ≤ t ≤ 10).
c) Find equations representing the waveform over the second period
(ie 10 ≤ t ≤ 20).
Solution:
a) The period is the time of one full cycle
T = 10 seconds
b) Equation for line (1) 0 ≤ t ≤ 4; (v in volts, t in seconds)
v(t) = m t + b; m = ∆v / ∆t = (v2 - v1) / (t2 - t1) = (8-0) / (4-0) = 2
\ v = 2 t + b; b = 0, by inspection of graph
\ v = 2 t; (0 ≤ t ≤ 4)
Equation for line (2) 4 ≤ t ≤ 10; (v in volts, t in seconds)
v(t) = m t + b; m = ∆v / ∆t = (v2 - v1) / (t2 - t1) = (0-8) / (10-4) = -8 / 6 = -4 / 3 » -1.33
\ v = - 4/3 t + b; to find "b", note that line (2) passes thru point (10, 0)
\ 0 = -4/3 (10) + b; --> b = 40/3
\ v = - 4/3 t + 40/3; (4 ≤ t ≤ 10)
or OK to write
v = -1.33 t + 13.33; (4 ≤ t ≤ 10)
b) Find equations for line segments representing second period (10 ≤ t ≤ 20)
easy if we shifting concept
v = 2(t - T)
v = 2(t - 10) or v = 2t - 20; (10 ≤ t ≤ 14)v = -4/3(t - 10) + 40/3 or v = -4/3t + 80/3; (14 ≤ t ≤ 20)
Note: could proceed in similar fashion to find equations for other cycles or periods.
Tuesday, May 31, 2011
Shifting Concept
We shifting concept to find equations for line segments representing others cycles or periods.
Ex. for second period (T ≤ t ≤ 2T) ==> f(t - T)
ie. f(t) when 0 ≤ t ≤ T = f(t - T) when T ≤ t ≤ 2T
Ex. for second period (T ≤ t ≤ 2T) ==> f(t - T)
ie. f(t) when 0 ≤ t ≤ T = f(t - T) when T ≤ t ≤ 2T
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